[Oberon] Modulus on negative number
Jörg
joerg.straube at iaeth.ch
Sat May 13 11:13:19 CEST 2017
Hi
Just for completeness, the result should be
1 MOD -12 = -11
-1 MOD -12 = -1
Jörg
> Am 13.05.2017 um 10:12 schrieb Peter Matthias <PeterMatthias at web.de>:
>
> Agreed. However, -1 MOD -12 or 1 MOD -12 is not defined in Oberon.
>
>
> Am 12.05.2017 um 22:43 schrieb Aubrey McIntosh:
>> for -1 MOD 12, the mathematically correct answers which are consistent
>> with the language report, are
>> q=-1, r=11.
>>
>> This definition works very well, for example, to implement wrap around
>> strip chart displays.
>>
>>
>> On Fri, May 12, 2017 at 2:28 PM, Peter Matthias <PeterMatthias at web.de
>> <mailto:PeterMatthias at web.de>> wrote:
>>
>> Warming up the thread to give supposedly correct answer:
>>
>> Am 16.02.2017 um 00:00 schrieb Peter Matthias:
>>
>>
>>
>> Am 15.02.2017 um 04:21 schrieb Srinivas Nayak:
>>
>> Dear All,
>>
>> Recently I come across modulus on a negative number.
>> Will it produce a negative number or positive?
>> Someone says both are correct!
>> http://stackoverflow.com/a/4403556
>> <http://stackoverflow.com/a/4403556>
>> Which one is mathematically correct?
>> Surprisingly different languages calculate it differently even!
>> What is Oberon's way?
>>
>>
>> The theory was already answered. In practice, all compiler
>> implementations I used (native X86, Shark, MIPS), give wrong
>> result when
>> both, divident and divisor are negative. I fixed it just
>> yesterday for
>> all non x86 versions.
>>
>>
>> I should have read the language report before making such claims.
>>
>> Oberon Report says:
>>
>> "The operators DIV and MOD apply to integer operands only. They are
>> related by the following formulas defined for any dividend x and
>> positive divisors y:
>> x = (x DIV y) * y + (x MOD y)
>> 0 ≤ (x MOD y) < y"
>>
>> Oberon07-Report says:
>>
>> "The operators DIV and MOD apply to integer operands only. Let q = x
>> DIV y, and r = x MOD y.
>> Then quotient q and remainder r are defined by the equation
>> x = q*y + r 0 <= r < y"
>>
>> Last statement obviously cannot be met if y is negative.
>>
>> So in short: Don't use DIV/MOD for negative divisors as the result
>> is not defined.
>>
>> >From the implemtation point of view this perfectly makes sense as
>> negative divisors are seldom used and correction for DIV of the
>> usually stupid hardware implementation only takes 3 additional
>> instructions compared to at least 6 for a complete definition.
>> Simple SHIFT/AND instructions for power of 2 divisors easily
>> outwight these 3 additional instructions.
>>
>>
>> Peter
>>
>> --
>> Oberon at lists.inf.ethz.ch <mailto:Oberon at lists.inf.ethz.ch> mailing
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>>
>>
>>
>>
>> --
>> Aubrey McIntosh, Ph.D.
>> 1502 Devon Circle
>> Austin TX 78723
>> (512) 348-7401
>>
>>
>>
>> --
>> Oberon at lists.inf.ethz.ch mailing list for ETH Oberon and related systems
>> https://lists.inf.ethz.ch/mailman/listinfo/oberon
>>
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